Hey Dieselboy,
Thanks for the help! Really appreciate the explanation and the pic you shared.
So.... Here's my understanding before I relay it to the rest of the peanut gallery.
1.) When the question states that the NEW subnet should use a 28-bit mask,
- I subtracted 16 from 80 in 10.0.155.*80*
(because /28 the subnets are increments of 16)
- I'm left with 10.0.155.64/28
(now with this info, moving on to the next part to replace the static route)
- I think I got this part down and digested in my brain.
2.) For the static route, I don't know where to begin to find why the mask is /27
- but my first clue is 10.0.155.64 and 10.0.155.80 from part 1
(need to include the old and new network)
- I understand /27 goes by increments of .32 , therefore..... 32 -> 64 -> 96
- so I know 10.0.155.64 in both /27 and /28 begin their subnet at .64
***now this part below, I need this part validated by an expert***
- If 10.0.155.64 /27 has a range of .64 through .95, it also includes 10.0.155.*80* (thus the old network)
- Being that it is in range, this would be the right answer?
3.) 10.0.155.80 /26 or /27 wouldn't work because the increments of the subnets in dotted decimal doesn't allow for .80?!
/26 = 0, 64, 128 ..... NO 80!
/27 = 0, 32, 64, 96 ..... NO 80!
(man... I get anxiety when having to answer, hahaha)
Thanks for the help! Really appreciate the explanation and the pic you shared.
So.... Here's my understanding before I relay it to the rest of the peanut gallery.
1.) When the question states that the NEW subnet should use a 28-bit mask,
- I subtracted 16 from 80 in 10.0.155.*80*
(because /28 the subnets are increments of 16)
- I'm left with 10.0.155.64/28
(now with this info, moving on to the next part to replace the static route)
- I think I got this part down and digested in my brain.
2.) For the static route, I don't know where to begin to find why the mask is /27
- but my first clue is 10.0.155.64 and 10.0.155.80 from part 1
(need to include the old and new network)
- I understand /27 goes by increments of .32 , therefore..... 32 -> 64 -> 96
- so I know 10.0.155.64 in both /27 and /28 begin their subnet at .64
***now this part below, I need this part validated by an expert***
- If 10.0.155.64 /27 has a range of .64 through .95, it also includes 10.0.155.*80* (thus the old network)
- Being that it is in range, this would be the right answer?
3.) 10.0.155.80 /26 or /27 wouldn't work because the increments of the subnets in dotted decimal doesn't allow for .80?!
/26 = 0, 64, 128 ..... NO 80!
/27 = 0, 32, 64, 96 ..... NO 80!
(man... I get anxiety when having to answer, hahaha)